How to pass function-pointer to a function in c++?

How to pass function-pointer to a function in c++?

Here is three functions such as:-
float Plus (float a, float b) { return a+b; }
float Minus (float a, float b) { return a-b; }
float Multiply(float a, float b) { return a*b; }
now there is function which takes pointer to a function as one of the
argument:-
void Function_Pointer_func(float a, float b, float (*pt2Func)(float, float))
{
float result = pt2Func(a, b); // call using function pointer
cout << " Result = "; // display result
cout << result << endl;
}
and to call the above function "Function_Pointer_func" the function is
written below
void Replace()
{
Function_Pointer_func(2, 5, /* pointer to function 'Minus' */
Plus);//// (1)
Function_Pointer_func(2, 5, /* pointer to function 'Minus' */
&Minus);//// (2)
}
Why does above function works fine as function "Function_Pointer_func"
takes function-pointer as argument. And if we replace RHS in line
float result = pt2Func(a, b); // call using function pointer
of function "Function_Pointer_func" by (*pt2Func)(a, b);then also it works
but for (&pt2Func)(a, b);
it gives an error of " error C2064: term does not evaluate to a function
taking 2 arguments " VS2008.
Now replace in the argument of "float (*pt2Func)(float, float)" in
function "Function_Pointer_func" by float (pt2Func)(float, float) then all
three
float result = pt2Func(a, b); //
float result = (&pt2Func)(a, b); //
float result = (*pt2Func)(a, b); //
statement works, why? I hope reason of my discomfort lies in understanding
the core understanding of function-pointer. Well, I am not presenting the
Q? without any good amount of reading but yes i haven't done any intensive
research on this so please feel free to recommend some reading in this
regard which will sort out my ambiguity.
Thanks for the help in advance.